Solve (frac{2*5-sqrt{400}}{2})-{-[3(3+1)]}

$$( \frac { 2 \times 5 - \sqrt { 400 } } { 2 } ) - \{ - [ 3 ( 3 + 1 ) ] \}$$

Evaluate

$$7$$

Solution Steps

Multiply 2 and 5 to get 10.

$$\frac{10-\sqrt{400}}{2}-\left(-3\left(3+1\right)\right)$$

Calculate the square root of 400 and get 20.

$$\frac{10-20}{2}-\left(-3\left(3+1\right)\right)$$

Subtract 20 from 10 to get -10.

$$\frac{-10}{2}-\left(-3\left(3+1\right)\right)$$

Divide -10 by 2 to get -5.

$$-5-\left(-3\left(3+1\right)\right)$$

Add 3 and 1 to get 4.

$$-5-\left(-3\times 4\right)$$

Multiply 3 and 4 to get 12.

$$-5-\left(-12\right)$$

The opposite of -12 is 12.

$$-5+12$$

Add -5 and 12 to get 7.

$$7$$

Factor

$$7$$