Solve (2^6/2^6*2^7/2)^3=

$$( \frac { 2 ^ { 6 } } { 2 ^ { 6 } } \times \frac { 2 ^ { 7 } } { 2 } ) ^ { 3 } =$$

Evaluate

$$262144$$

Solution Steps

Divide 2^{6} by 2^{6} to get 1.

$$\left(1\times \frac{2^{7}}{2}\right)^{3}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 7 to get 6.

$$\left(1\times 2^{6}\right)^{3}$$

Calculate 2 to the power of 6 and get 64.

$$\left(1\times 64\right)^{3}$$

Multiply 1 and 64 to get 64.

$$64^{3}$$

Calculate 64 to the power of 3 and get 262144.

$$262144$$

Factor

$$2^{18}$$