Solve (16/32)^3*(4/8)^5

$$( \frac { 16 } { 32 } ) ^ { 3 } \times ( \frac { 4 } { 8 } ) ^ { 5 }$$

Evaluate

$$\frac{1}{256}=0.00390625$$

Solution Steps

Reduce the fraction \frac{16}{32} to lowest terms by extracting and canceling out 16.

$$\left(\frac{1}{2}\right)^{3}\times \left(\frac{4}{8}\right)^{5}$$

Calculate \frac{1}{2} to the power of 3 and get \frac{1}{8}.

$$\frac{1}{8}\times \left(\frac{4}{8}\right)^{5}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\frac{1}{8}\times \left(\frac{1}{2}\right)^{5}$$

Calculate \frac{1}{2} to the power of 5 and get \frac{1}{32}.

$$\frac{1}{8}\times \frac{1}{32}$$

Multiply \frac{1}{8} and \frac{1}{32} to get \frac{1}{256}.

$$\frac{1}{256}$$

Factor

$$\frac{1}{2 ^ {8}} = 0.00390625$$