Solve (16/12+3/3-2/4)-3

$$( \frac { 16 } { 12 } + \frac { 3 } { 3 } - \frac { 2 } { 4 } ) - 3$$

Evaluate

$$-\frac{7}{6}\approx -1.166666667$$

Solution Steps

Divide 3 by 3 to get 1.

$$\frac{16}{12}+1-\frac{2}{4}-3$$

Reduce the fraction \frac{16}{12} to lowest terms by extracting and canceling out 4.

$$\frac{4}{3}+1-\frac{2}{4}-3$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{4}{3}+\frac{3}{3}-\frac{2}{4}-3$$

Since \frac{4}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{4+3}{3}-\frac{2}{4}-3$$

Add 4 and 3 to get 7.

$$\frac{7}{3}-\frac{2}{4}-3$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{7}{3}-\frac{1}{2}-3$$

Least common multiple of 3 and 2 is 6. Convert \frac{7}{3} and \frac{1}{2} to fractions with denominator 6.

$$\frac{14}{6}-\frac{3}{6}-3$$

Since \frac{14}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-3}{6}-3$$

Subtract 3 from 14 to get 11.

$$\frac{11}{6}-3$$

Convert 3 to fraction \frac{18}{6}.

$$\frac{11}{6}-\frac{18}{6}$$

Since \frac{11}{6} and \frac{18}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11-18}{6}$$

Subtract 18 from 11 to get -7.

$$-\frac{7}{6}$$

Factor

$$-\frac{7}{6} = -1\frac{1}{6} = -1.1666666666666667$$