Solve (11/9*15+6/10*10)*100/25

$$( \frac { 11 } { 9 } \times 15 + \frac { 6 } { 10 } \times 10 ) \times \frac { 100 } { 25 }$$

Evaluate

$$\frac{292}{3}\approx 97.333333333$$

Solution Steps

Express \frac{11}{9}\times 15 as a single fraction.

$$\left(\frac{11\times 15}{9}+\frac{6}{10}\times 10\right)\times \frac{100}{25}$$

Multiply 11 and 15 to get 165.

$$\left(\frac{165}{9}+\frac{6}{10}\times 10\right)\times \frac{100}{25}$$

Reduce the fraction \frac{165}{9} to lowest terms by extracting and canceling out 3.

$$\left(\frac{55}{3}+\frac{6}{10}\times 10\right)\times \frac{100}{25}$$

Reduce the fraction \frac{6}{10} to lowest terms by extracting and canceling out 2.

$$\left(\frac{55}{3}+\frac{3}{5}\times 10\right)\times \frac{100}{25}$$

Express \frac{3}{5}\times 10 as a single fraction.

$$\left(\frac{55}{3}+\frac{3\times 10}{5}\right)\times \frac{100}{25}$$

Multiply 3 and 10 to get 30.

$$\left(\frac{55}{3}+\frac{30}{5}\right)\times \frac{100}{25}$$

Divide 30 by 5 to get 6.

$$\left(\frac{55}{3}+6\right)\times \frac{100}{25}$$

Convert 6 to fraction \frac{18}{3}.

$$\left(\frac{55}{3}+\frac{18}{3}\right)\times \frac{100}{25}$$

Since \frac{55}{3} and \frac{18}{3} have the same denominator, add them by adding their numerators.

$$\frac{55+18}{3}\times \frac{100}{25}$$

Add 55 and 18 to get 73.

$$\frac{73}{3}\times \frac{100}{25}$$

Divide 100 by 25 to get 4.

$$\frac{73}{3}\times 4$$

Express \frac{73}{3}\times 4 as a single fraction.

$$\frac{73\times 4}{3}$$

Multiply 73 and 4 to get 292.

$$\frac{292}{3}$$

Factor

$$\frac{2 ^ {2} \cdot 73}{3} = 97\frac{1}{3} = 97.33333333333333$$