Solve (11/30-17/36):19/45

$$( \frac { 11 } { 30 } - \frac { 17 } { 36 } ) : \frac { 19 } { 45 }$$

Evaluate

$$-\frac{1}{4}=-0.25$$

Solution Steps

Least common multiple of 30 and 36 is 180. Convert \frac{11}{30} and \frac{17}{36} to fractions with denominator 180.

$$\frac{\frac{66}{180}-\frac{85}{180}}{\frac{19}{45}}$$

Since \frac{66}{180} and \frac{85}{180} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{66-85}{180}}{\frac{19}{45}}$$

Subtract 85 from 66 to get -19.

$$\frac{-\frac{19}{180}}{\frac{19}{45}}$$

Divide -\frac{19}{180} by \frac{19}{45} by multiplying -\frac{19}{180} by the reciprocal of \frac{19}{45}.

$$-\frac{19}{180}\times \frac{45}{19}$$

Multiply -\frac{19}{180} times \frac{45}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-19\times 45}{180\times 19}$$

Do the multiplications in the fraction \frac{-19\times 45}{180\times 19}.

$$\frac{-855}{3420}$$

Reduce the fraction \frac{-855}{3420} to lowest terms by extracting and canceling out 855.

$$-\frac{1}{4}$$

Factor

$$-\frac{1}{4} = -0.25$$