Solve (11/180-1/45)(90*1/11)=

$$( \frac { 11 } { 180 } - \frac { 1 } { 45 } ) ( 90 \times \frac { 1 } { 11 } ) =$$

Evaluate

$$\frac{7}{22}\approx 0.318181818$$

Solution Steps

Least common multiple of 180 and 45 is 180. Convert \frac{11}{180} and \frac{1}{45} to fractions with denominator 180.

$$\left(\frac{11}{180}-\frac{4}{180}\right)\times 90\times \frac{1}{11}$$

Since \frac{11}{180} and \frac{4}{180} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11-4}{180}\times 90\times \frac{1}{11}$$

Subtract 4 from 11 to get 7.

$$\frac{7}{180}\times 90\times \frac{1}{11}$$

Express \frac{7}{180}\times 90 as a single fraction.

$$\frac{7\times 90}{180}\times \frac{1}{11}$$

Multiply 7 and 90 to get 630.

$$\frac{630}{180}\times \frac{1}{11}$$

Reduce the fraction \frac{630}{180} to lowest terms by extracting and canceling out 90.

$$\frac{7}{2}\times \frac{1}{11}$$

Multiply \frac{7}{2} times \frac{1}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 1}{2\times 11}$$

Do the multiplications in the fraction \frac{7\times 1}{2\times 11}.

$$\frac{7}{22}$$

Factor

$$\frac{7}{2 \cdot 11} = 0.3181818181818182$$