Solve (1/9-1/2)*4/3

$$( \frac { 1 } { 9 } - \frac { 1 } { 2 } ) \cdot \frac { 4 } { 3 }$$

Evaluate

$$-\frac{14}{27}\approx -0.518518519$$

Solution Steps

Least common multiple of 9 and 2 is 18. Convert \frac{1}{9} and \frac{1}{2} to fractions with denominator 18.

$$\left(\frac{2}{18}-\frac{9}{18}\right)\times \frac{4}{3}$$

Since \frac{2}{18} and \frac{9}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-9}{18}\times \frac{4}{3}$$

Subtract 9 from 2 to get -7.

$$-\frac{7}{18}\times \frac{4}{3}$$

Multiply -\frac{7}{18} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-7\times 4}{18\times 3}$$

Do the multiplications in the fraction \frac{-7\times 4}{18\times 3}.

$$\frac{-28}{54}$$

Reduce the fraction \frac{-28}{54} to lowest terms by extracting and canceling out 2.

$$-\frac{14}{27}$$

Factor

$$-\frac{14}{27} = -0.5185185185185185$$