Solve (1/9+1/6-1/4)*(-36)

$$( \frac { 1 } { 9 } + \frac { 1 } { 6 } - \frac { 1 } { 4 } ) \times ( - 36 )$$

Evaluate

$$-1$$

Solution Steps

Least common multiple of 9 and 6 is 18. Convert \frac{1}{9} and \frac{1}{6} to fractions with denominator 18.

$$\left(\frac{2}{18}+\frac{3}{18}-\frac{1}{4}\right)\left(-36\right)$$

Since \frac{2}{18} and \frac{3}{18} have the same denominator, add them by adding their numerators.

$$\left(\frac{2+3}{18}-\frac{1}{4}\right)\left(-36\right)$$

Add 2 and 3 to get 5.

$$\left(\frac{5}{18}-\frac{1}{4}\right)\left(-36\right)$$

Least common multiple of 18 and 4 is 36. Convert \frac{5}{18} and \frac{1}{4} to fractions with denominator 36.

$$\left(\frac{10}{36}-\frac{9}{36}\right)\left(-36\right)$$

Since \frac{10}{36} and \frac{9}{36} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-9}{36}\left(-36\right)$$

Subtract 9 from 10 to get 1.

$$\frac{1}{36}\left(-36\right)$$

Multiply \frac{1}{36} and -36 to get \frac{-36}{36}.

$$\frac{-36}{36}$$

Divide -36 by 36 to get -1.

$$-1$$

Factor

$$-1$$