Solve (1/8+10/8-2/8):(-2/10-frac{15}{10}+frac{60}{10}+frac{17}{10})

$$( \frac { 1 } { 8 } + \frac { 10 } { 8 } - \frac { 2 } { 8 } ) : ( - \frac { 2 } { 10 } - \frac { 15 } { 10 } + \frac { 60 } { 10 } + \frac { 17 } { 10 } )$$

Evaluate

$$\frac{3}{16}=0.1875$$

Solution Steps

Since \frac{1}{8} and \frac{10}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1+10}{8}-\frac{2}{8}}{-\frac{2}{10}-\frac{15}{10}+\frac{60}{10}+\frac{17}{10}}$$

Add 1 and 10 to get 11.

$$\frac{\frac{11}{8}-\frac{2}{8}}{-\frac{2}{10}-\frac{15}{10}+\frac{60}{10}+\frac{17}{10}}$$

Since \frac{11}{8} and \frac{2}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{11-2}{8}}{-\frac{2}{10}-\frac{15}{10}+\frac{60}{10}+\frac{17}{10}}$$

Subtract 2 from 11 to get 9.

$$\frac{\frac{9}{8}}{-\frac{2}{10}-\frac{15}{10}+\frac{60}{10}+\frac{17}{10}}$$

Since -\frac{2}{10} and \frac{15}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{9}{8}}{\frac{-2-15}{10}+\frac{60}{10}+\frac{17}{10}}$$

Subtract 15 from -2 to get -17.

$$\frac{\frac{9}{8}}{-\frac{17}{10}+\frac{60}{10}+\frac{17}{10}}$$

Since -\frac{17}{10} and \frac{60}{10} have the same denominator, add them by adding their numerators.

$$\frac{\frac{9}{8}}{\frac{-17+60}{10}+\frac{17}{10}}$$

Add -17 and 60 to get 43.

$$\frac{\frac{9}{8}}{\frac{43}{10}+\frac{17}{10}}$$

Since \frac{43}{10} and \frac{17}{10} have the same denominator, add them by adding their numerators.

$$\frac{\frac{9}{8}}{\frac{43+17}{10}}$$

Add 43 and 17 to get 60.

$$\frac{\frac{9}{8}}{\frac{60}{10}}$$

Divide 60 by 10 to get 6.

$$\frac{\frac{9}{8}}{6}$$

Express \frac{\frac{9}{8}}{6} as a single fraction.

$$\frac{9}{8\times 6}$$

Multiply 8 and 6 to get 48.

$$\frac{9}{48}$$

Reduce the fraction \frac{9}{48} to lowest terms by extracting and canceling out 3.

$$\frac{3}{16}$$

Factor

$$\frac{3}{2 ^ {4}} = 0.1875$$