Solve (1/6)^2+16/9+263/36

$$( \frac { 1 } { 6 } ) ^ { 2 } + \frac { 16 } { 9 } + \frac { 263 } { 36 }$$

Evaluate

$$\frac{82}{9}\approx 9.111111111$$

Solution Steps

Calculate \frac{1}{6} to the power of 2 and get \frac{1}{36}.

$$\frac{1}{36}+\frac{16}{9}+\frac{263}{36}$$

Least common multiple of 36 and 9 is 36. Convert \frac{1}{36} and \frac{16}{9} to fractions with denominator 36.

$$\frac{1}{36}+\frac{64}{36}+\frac{263}{36}$$

Since \frac{1}{36} and \frac{64}{36} have the same denominator, add them by adding their numerators.

$$\frac{1+64}{36}+\frac{263}{36}$$

Add 1 and 64 to get 65.

$$\frac{65}{36}+\frac{263}{36}$$

Since \frac{65}{36} and \frac{263}{36} have the same denominator, add them by adding their numerators.

$$\frac{65+263}{36}$$

Add 65 and 263 to get 328.

$$\frac{328}{36}$$

Reduce the fraction \frac{328}{36} to lowest terms by extracting and canceling out 4.

$$\frac{82}{9}$$

Factor

$$\frac{2 \cdot 41}{3 ^ {2}} = 9\frac{1}{9} = 9.11111111111111$$