Solve (1/5+2/10)*11/20=

$$( \frac { 1 } { 5 } + \frac { 2 } { 10 } ) \times 1 \frac { 1 } { 20 } =$$

Evaluate

$$\frac{21}{50}=0.42$$

Solution Steps

Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$\left(\frac{1}{5}+\frac{1}{5}\right)\times \frac{1\times 20+1}{20}$$

Since \frac{1}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$\frac{1+1}{5}\times \frac{1\times 20+1}{20}$$

Add 1 and 1 to get 2.

$$\frac{2}{5}\times \frac{1\times 20+1}{20}$$

Multiply 1 and 20 to get 20.

$$\frac{2}{5}\times \frac{20+1}{20}$$

Add 20 and 1 to get 21.

$$\frac{2}{5}\times \frac{21}{20}$$

Multiply \frac{2}{5} times \frac{21}{20} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 21}{5\times 20}$$

Do the multiplications in the fraction \frac{2\times 21}{5\times 20}.

$$\frac{42}{100}$$

Reduce the fraction \frac{42}{100} to lowest terms by extracting and canceling out 2.

$$\frac{21}{50}$$

Factor

$$\frac{3 \cdot 7}{2 \cdot 5 ^ {2}} = 0.42$$