Evaluate
\frac{\left(3a-4b\right)^{2}}{144}
Expand
-\frac{ab}{6}+\frac{a^{2}}{16}+\frac{b^{2}}{9}
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\frac{1}{16}a^{2}-\frac{1}{6}ab+\frac{1}{9}b^{2}
Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(\frac{1}{4}a-\frac{1}{3}b\right)^{2}.
\frac{1}{16}a^{2}-\frac{1}{6}ab+\frac{1}{9}b^{2}
Use binomial theorem \left(p-q\right)^{2}=p^{2}-2pq+q^{2} to expand \left(\frac{1}{4}a-\frac{1}{3}b\right)^{2}.
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