Solve (1/4)^3-(1/4)^2m-25(1/4)+6=0

$$( \frac { 1 } { 4 } ) ^ { 3 } - ( \frac { 1 } { 4 } ) ^ { 2 } m - 25 ( \frac { 1 } { 4 } ) + 6 = 0$$

Solve for m

$$m = -\frac{15}{4} = -3\frac{3}{4} = -3.75$$

Steps for Solving Linear Equation

Calculate \frac{1}{4} to the power of 3 and get \frac{1}{64}.

$$\frac{1}{64}-\left(\frac{1}{4}\right)^{2}m-25\times \frac{1}{4}+6=0$$

Calculate \frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$\frac{1}{64}-\frac{1}{16}m-25\times \frac{1}{4}+6=0$$

Multiply 25 and \frac{1}{4} to get \frac{25}{4}.

$$\frac{1}{64}-\frac{1}{16}m-\frac{25}{4}+6=0$$

Least common multiple of 64 and 4 is 64. Convert \frac{1}{64} and \frac{25}{4} to fractions with denominator 64.

$$\frac{1}{64}-\frac{1}{16}m-\frac{400}{64}+6=0$$

Since \frac{1}{64} and \frac{400}{64} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-400}{64}-\frac{1}{16}m+6=0$$

Subtract 400 from 1 to get -399.

$$-\frac{399}{64}-\frac{1}{16}m+6=0$$

Convert 6 to fraction \frac{384}{64}.

$$-\frac{399}{64}-\frac{1}{16}m+\frac{384}{64}=0$$

Since -\frac{399}{64} and \frac{384}{64} have the same denominator, add them by adding their numerators.

$$\frac{-399+384}{64}-\frac{1}{16}m=0$$

Add -399 and 384 to get -15.

$$-\frac{15}{64}-\frac{1}{16}m=0$$

Add \frac{15}{64} to both sides. Anything plus zero gives itself.

$$-\frac{1}{16}m=\frac{15}{64}$$

Multiply both sides by -16, the reciprocal of -\frac{1}{16}.

$$m=\frac{15}{64}\left(-16\right)$$

Express \frac{15}{64}\left(-16\right) as a single fraction.

$$m=\frac{15\left(-16\right)}{64}$$

Multiply 15 and -16 to get -240.

$$m=\frac{-240}{64}$$

Reduce the fraction \frac{-240}{64} to lowest terms by extracting and canceling out 16.

$$m=-\frac{15}{4}$$