Solve (1/4)^3+3(1/4)=48

$$( \frac { 1 } { 4 } ) ^ { 3 } + 3 ( \frac { 1 } { 4 } ) = 48$$

Verify

Solution Steps

Calculate \frac{1}{4} to the power of 3 and get \frac{1}{64}.

$$\frac{1}{64}+3\times \frac{1}{4}=48$$

Multiply 3 and \frac{1}{4} to get \frac{3}{4}.

$$\frac{1}{64}+\frac{3}{4}=48$$

Least common multiple of 64 and 4 is 64. Convert \frac{1}{64} and \frac{3}{4} to fractions with denominator 64.

$$\frac{1}{64}+\frac{48}{64}=48$$

Since \frac{1}{64} and \frac{48}{64} have the same denominator, add them by adding their numerators.

$$\frac{1+48}{64}=48$$

Add 1 and 48 to get 49.

$$\frac{49}{64}=48$$

Convert 48 to fraction \frac{3072}{64}.

$$\frac{49}{64}=\frac{3072}{64}$$

Compare \frac{49}{64} and \frac{3072}{64}.

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