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\left(\frac{1}{3}x\right)^{2}-\left(\frac{1}{2}y\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\left(\frac{1}{3}\right)^{2}x^{2}-\left(\frac{1}{2}y\right)^{2}
Expand \left(\frac{1}{3}x\right)^{2}.
\frac{1}{9}x^{2}-\left(\frac{1}{2}y\right)^{2}
Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.
\frac{1}{9}x^{2}-\left(\frac{1}{2}\right)^{2}y^{2}
Expand \left(\frac{1}{2}y\right)^{2}.
\frac{1}{9}x^{2}-\frac{1}{4}y^{2}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
\left(\frac{1}{3}x\right)^{2}-\left(\frac{1}{2}y\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\left(\frac{1}{3}\right)^{2}x^{2}-\left(\frac{1}{2}y\right)^{2}
Expand \left(\frac{1}{3}x\right)^{2}.
\frac{1}{9}x^{2}-\left(\frac{1}{2}y\right)^{2}
Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.
\frac{1}{9}x^{2}-\left(\frac{1}{2}\right)^{2}y^{2}
Expand \left(\frac{1}{2}y\right)^{2}.
\frac{1}{9}x^{2}-\frac{1}{4}y^{2}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.