Solve (1/3-2)(2*1/3-1)

$$( \frac { 1 } { 3 } - 2 ) ( 2 \times \frac { 1 } { 3 } - 1 )$$

Evaluate

$$\frac{5}{9}\approx 0.555555556$$

Solution Steps

Convert 2 to fraction \frac{6}{3}.

$$\left(\frac{1}{3}-\frac{6}{3}\right)\left(2\times \frac{1}{3}-1\right)$$

Since \frac{1}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-6}{3}\left(2\times \frac{1}{3}-1\right)$$

Subtract 6 from 1 to get -5.

$$-\frac{5}{3}\left(2\times \frac{1}{3}-1\right)$$

Multiply 2 and \frac{1}{3} to get \frac{2}{3}.

$$-\frac{5}{3}\left(\frac{2}{3}-1\right)$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{5}{3}\left(\frac{2}{3}-\frac{3}{3}\right)$$

Since \frac{2}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{5}{3}\times \frac{2-3}{3}$$

Subtract 3 from 2 to get -1.

$$-\frac{5}{3}\left(-\frac{1}{3}\right)$$

Multiply -\frac{5}{3} times -\frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-5\left(-1\right)}{3\times 3}$$

Do the multiplications in the fraction \frac{-5\left(-1\right)}{3\times 3}.

$$\frac{5}{9}$$

Factor

$$\frac{5}{3 ^ {2}} = 0.5555555555555556$$