Solve (1/3-7/2+19/6)

$$( \frac { 1 } { 3 } - \frac { 7 } { 2 } + \frac { 19 } { 6 } )$$

Evaluate

$$0$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{1}{3} and \frac{7}{2} to fractions with denominator 6.

$$\frac{2}{6}-\frac{21}{6}+\frac{19}{6}$$

Since \frac{2}{6} and \frac{21}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-21}{6}+\frac{19}{6}$$

Subtract 21 from 2 to get -19.

$$-\frac{19}{6}+\frac{19}{6}$$

Add -\frac{19}{6} and \frac{19}{6} to get 0.

$$0$$

Factor

$$0$$