Solve (1/3-4/5+4/2)*1/3

$$( \frac { 1 } { 3 } - \frac { 4 } { 5 } + \frac { 4 } { 2 } ) \cdot \frac { 1 } { 3 }$$

Evaluate

$$\frac{23}{45}\approx 0.511111111$$

Solution Steps

Least common multiple of 3 and 5 is 15. Convert \frac{1}{3} and \frac{4}{5} to fractions with denominator 15.

$$\left(\frac{5}{15}-\frac{12}{15}+\frac{4}{2}\right)\times \frac{1}{3}$$

Since \frac{5}{15} and \frac{12}{15} have the same denominator, subtract them by subtracting their numerators.

$$\left(\frac{5-12}{15}+\frac{4}{2}\right)\times \frac{1}{3}$$

Subtract 12 from 5 to get -7.

$$\left(-\frac{7}{15}+\frac{4}{2}\right)\times \frac{1}{3}$$

Divide 4 by 2 to get 2.

$$\left(-\frac{7}{15}+2\right)\times \frac{1}{3}$$

Convert 2 to fraction \frac{30}{15}.

$$\left(-\frac{7}{15}+\frac{30}{15}\right)\times \frac{1}{3}$$

Since -\frac{7}{15} and \frac{30}{15} have the same denominator, add them by adding their numerators.

$$\frac{-7+30}{15}\times \frac{1}{3}$$

Add -7 and 30 to get 23.

$$\frac{23}{15}\times \frac{1}{3}$$

Multiply \frac{23}{15} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{23\times 1}{15\times 3}$$

Do the multiplications in the fraction \frac{23\times 1}{15\times 3}.

$$\frac{23}{45}$$

Factor

$$\frac{23}{3 ^ {2} \cdot 5} = 0.5111111111111111$$