Solve (1/3)^4*(9/5)^3=

$$( \frac { 1 } { 3 } ) ^ { 4 } \times ( \frac { 9 } { 5 } ) ^ { 3 } =$$

Evaluate

$$\frac{9}{125}=0.072$$

Solution Steps

Calculate \frac{1}{3} to the power of 4 and get \frac{1}{81}.

$$\frac{1}{81}\times \left(\frac{9}{5}\right)^{3}$$

Calculate \frac{9}{5} to the power of 3 and get \frac{729}{125}.

$$\frac{1}{81}\times \frac{729}{125}$$

Multiply \frac{1}{81} times \frac{729}{125} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 729}{81\times 125}$$

Do the multiplications in the fraction \frac{1\times 729}{81\times 125}.

$$\frac{729}{10125}$$

Reduce the fraction \frac{729}{10125} to lowest terms by extracting and canceling out 81.

$$\frac{9}{125}$$

Factor

$$\frac{3 ^ {2}}{5 ^ {3}} = 0.072$$