Solve (1/3)^3+4/9

$$( \frac { 1 } { 3 } ) ^ { 3 } + \frac { 4 } { 9 }$$

Evaluate

$$\frac{13}{27}\approx 0.481481481$$

Solution Steps

Calculate \frac{1}{3} to the power of 3 and get \frac{1}{27}.

$$\frac{1}{27}+\frac{4}{9}$$

Least common multiple of 27 and 9 is 27. Convert \frac{1}{27} and \frac{4}{9} to fractions with denominator 27.

$$\frac{1}{27}+\frac{12}{27}$$

Since \frac{1}{27} and \frac{12}{27} have the same denominator, add them by adding their numerators.

$$\frac{1+12}{27}$$

Add 1 and 12 to get 13.

$$\frac{13}{27}$$

Factor

$$\frac{13}{3 ^ {3}} = 0.48148148148148145$$