Solve (1/3)^2div(1/3+3/4)^2

$$( \frac { 1 } { 3 } ) ^ { 2 } \div ( \frac { 1 } { 3 } + \frac { 3 } { 4 } ) ^ { 2 }$$

Evaluate

$$\frac{16}{169}\approx 0.094674556$$

Solution Steps

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{\frac{1}{9}}{\left(\frac{1}{3}+\frac{3}{4}\right)^{2}}$$

Add \frac{1}{3} and \frac{3}{4} to get \frac{13}{12}.

$$\frac{\frac{1}{9}}{\left(\frac{13}{12}\right)^{2}}$$

Calculate \frac{13}{12} to the power of 2 and get \frac{169}{144}.

$$\frac{\frac{1}{9}}{\frac{169}{144}}$$

Divide \frac{1}{9} by \frac{169}{144} by multiplying \frac{1}{9} by the reciprocal of \frac{169}{144}.

$$\frac{1}{9}\times \frac{144}{169}$$

Multiply \frac{1}{9} and \frac{144}{169} to get \frac{16}{169}.

$$\frac{16}{169}$$

Factor

$$\frac{2 ^ {4}}{13 ^ {2}} = 0.09467455621301775$$