Solve (1/3*(3)^3)-(1/3*2^3)

$$( \frac { 1 } { 3 } \cdot ( 3 ) ^ { 3 } ) - ( \frac { 1 } { 3 } \cdot 2 ^ { 3 } )$$

Evaluate

$$\frac{19}{3}\approx 6.333333333$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$\frac{1}{3}\times 27-\frac{1}{3}\times 2^{3}$$

Multiply \frac{1}{3} and 27 to get \frac{27}{3}.

$$\frac{27}{3}-\frac{1}{3}\times 2^{3}$$

Divide 27 by 3 to get 9.

$$9-\frac{1}{3}\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$9-\frac{1}{3}\times 8$$

Multiply \frac{1}{3} and 8 to get \frac{8}{3}.

$$9-\frac{8}{3}$$

Convert 9 to fraction \frac{27}{3}.

$$\frac{27}{3}-\frac{8}{3}$$

Since \frac{27}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{27-8}{3}$$

Subtract 8 from 27 to get 19.

$$\frac{19}{3}$$

Factor

$$\frac{19}{3} = 6\frac{1}{3} = 6.333333333333333$$