Solve (1/25)^0+frac{1/4*16+sqrt[4]{16}}{2^-1}

$$( \frac { 1 } { 25 } ) ^ { 0 } + \frac { \frac { 1 } { 4 } \cdot 16 + \sqrt[ 4 ] { 16 } } { 2 ^ { - 1 } }$$

Evaluate

$$13$$

Solution Steps

Calculate \frac{1}{25} to the power of 0 and get 1.

$$1+\frac{\frac{1}{4}\times 16+\sqrt[4]{16}}{2^{-1}}$$

Multiply \frac{1}{4} and 16 to get 4.

$$1+\frac{4+\sqrt[4]{16}}{2^{-1}}$$

Calculate \sqrt[4]{16} and get 2.

$$1+\frac{4+2}{2^{-1}}$$

Add 4 and 2 to get 6.

$$1+\frac{6}{2^{-1}}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$1+\frac{6}{\frac{1}{2}}$$

Divide 6 by \frac{1}{2} by multiplying 6 by the reciprocal of \frac{1}{2}.

$$1+6\times 2$$

Multiply 6 and 2 to get 12.

$$1+12$$

Add 1 and 12 to get 13.

$$13$$

Factor

$$13$$