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-4
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\left(\frac{1}{2}x\right)^{2}-4-\frac{1}{4}x^{2}
Consider \left(\frac{1}{2}x-2\right)\left(\frac{1}{2}x+2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 2.
\left(\frac{1}{2}\right)^{2}x^{2}-4-\frac{1}{4}x^{2}
Expand \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-4-\frac{1}{4}x^{2}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
-4
Combine \frac{1}{4}x^{2} and -\frac{1}{4}x^{2} to get 0.
\frac{\left(x-4\right)\left(x+4\right)-x^{2}}{4}
Factor out \frac{1}{4}.
-4
Simplify.
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