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\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{2}x-1\right)^{2}.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x\right)^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Consider \left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}\right)^{2}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Expand \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-x+1+\frac{1}{4}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{1}{2}x^{2}-x+1-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Combine \frac{1}{4}x^{2} and \frac{1}{4}x^{2} to get \frac{1}{2}x^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Subtract 1 from 1 to get 0.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x\right)^{2}-1
Consider \left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}\right)^{2}x^{2}-1
Expand \left(-\frac{1}{2}x\right)^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\frac{1}{4}x^{2}-1
Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{3}{4}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}-1
Combine \frac{1}{2}x^{2} and \frac{1}{4}x^{2} to get \frac{3}{4}x^{2}.
\frac{3}{4}x^{2}-x+\frac{1}{4}x^{2}+x+1-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\frac{1}{2}x+1\right)^{2}.
x^{2}-x+x+1-1
Combine \frac{3}{4}x^{2} and \frac{1}{4}x^{2} to get x^{2}.
x^{2}+1-1
Combine -x and x to get 0.
x^{2}
Subtract 1 from 1 to get 0.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right)+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{2}x-1\right)^{2}.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}x\right)^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Consider \left(\frac{1}{2}x-1\right)\left(\frac{1}{2}x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
\frac{1}{4}x^{2}-x+1+\left(\frac{1}{2}\right)^{2}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Expand \left(\frac{1}{2}x\right)^{2}.
\frac{1}{4}x^{2}-x+1+\frac{1}{4}x^{2}-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{1}{2}x^{2}-x+1-1+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Combine \frac{1}{4}x^{2} and \frac{1}{4}x^{2} to get \frac{1}{2}x^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right)
Subtract 1 from 1 to get 0.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}x\right)^{2}-1
Consider \left(-\frac{1}{2}x-1\right)\left(-\frac{1}{2}x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\left(-\frac{1}{2}\right)^{2}x^{2}-1
Expand \left(-\frac{1}{2}x\right)^{2}.
\frac{1}{2}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}+\frac{1}{4}x^{2}-1
Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{3}{4}x^{2}-x+\left(\frac{1}{2}x+1\right)^{2}-1
Combine \frac{1}{2}x^{2} and \frac{1}{4}x^{2} to get \frac{3}{4}x^{2}.
\frac{3}{4}x^{2}-x+\frac{1}{4}x^{2}+x+1-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\frac{1}{2}x+1\right)^{2}.
x^{2}-x+x+1-1
Combine \frac{3}{4}x^{2} and \frac{1}{4}x^{2} to get x^{2}.
x^{2}+1-1
Combine -x and x to get 0.
x^{2}
Subtract 1 from 1 to get 0.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}