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\frac{1}{4}x^{2}+3x+9-\left(\frac{1}{2}x-3\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\frac{1}{2}x+3\right)^{2}.
\frac{1}{4}x^{2}+3x+9-\left(\frac{1}{4}x^{2}-3x+9\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{2}x-3\right)^{2}.
\frac{1}{4}x^{2}+3x+9-\frac{1}{4}x^{2}+3x-9
To find the opposite of \frac{1}{4}x^{2}-3x+9, find the opposite of each term.
3x+9+3x-9
Combine \frac{1}{4}x^{2} and -\frac{1}{4}x^{2} to get 0.
6x+9-9
Combine 3x and 3x to get 6x.
6x
Subtract 9 from 9 to get 0.
\frac{1}{4}x^{2}+3x+9-\left(\frac{1}{2}x-3\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\frac{1}{2}x+3\right)^{2}.
\frac{1}{4}x^{2}+3x+9-\left(\frac{1}{4}x^{2}-3x+9\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{2}x-3\right)^{2}.
\frac{1}{4}x^{2}+3x+9-\frac{1}{4}x^{2}+3x-9
To find the opposite of \frac{1}{4}x^{2}-3x+9, find the opposite of each term.
3x+9+3x-9
Combine \frac{1}{4}x^{2} and -\frac{1}{4}x^{2} to get 0.
6x+9-9
Combine 3x and 3x to get 6x.
6x
Subtract 9 from 9 to get 0.