Solve (1/2-41/6)*(-11/2)=

$$( \frac { 1 } { 2 } - 4 \frac { 1 } { 6 } ) \times ( - 1 \frac { 1 } { 2 } ) =$$

Evaluate

$$\frac{11}{2}=5.5$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\left(\frac{1}{2}-\frac{24+1}{6}\right)\left(-\frac{1\times 2+1}{2}\right)$$

Add 24 and 1 to get 25.

$$\left(\frac{1}{2}-\frac{25}{6}\right)\left(-\frac{1\times 2+1}{2}\right)$$

Least common multiple of 2 and 6 is 6. Convert \frac{1}{2} and \frac{25}{6} to fractions with denominator 6.

$$\left(\frac{3}{6}-\frac{25}{6}\right)\left(-\frac{1\times 2+1}{2}\right)$$

Since \frac{3}{6} and \frac{25}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-25}{6}\left(-\frac{1\times 2+1}{2}\right)$$

Subtract 25 from 3 to get -22.

$$\frac{-22}{6}\left(-\frac{1\times 2+1}{2}\right)$$

Reduce the fraction \frac{-22}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{11}{3}\left(-\frac{2+1}{2}\right)$$

Add 2 and 1 to get 3.

$$-\frac{11}{3}\left(-\frac{3}{2}\right)$$

Multiply -\frac{11}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-11\left(-3\right)}{3\times 2}$$

Do the multiplications in the fraction \frac{-11\left(-3\right)}{3\times 2}.

$$\frac{33}{6}$$

Reduce the fraction \frac{33}{6} to lowest terms by extracting and canceling out 3.

$$\frac{11}{2}$$

Factor

$$\frac{11}{2} = 5\frac{1}{2} = 5.5$$