Solve (1/2-4/3)*3/5

$$( \frac { 1 } { 2 } - \frac { 4 } { 3 } ) \cdot \frac { 3 } { 5 }$$

Evaluate

$$-\frac{1}{2}=-0.5$$

Solution Steps

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{4}{3} to fractions with denominator 6.

$$\left(\frac{3}{6}-\frac{8}{6}\right)\times \frac{3}{5}$$

Since \frac{3}{6} and \frac{8}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-8}{6}\times \frac{3}{5}$$

Subtract 8 from 3 to get -5.

$$-\frac{5}{6}\times \frac{3}{5}$$

Multiply -\frac{5}{6} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-5\times 3}{6\times 5}$$

Do the multiplications in the fraction \frac{-5\times 3}{6\times 5}.

$$\frac{-15}{30}$$

Reduce the fraction \frac{-15}{30} to lowest terms by extracting and canceling out 15.

$$-\frac{1}{2}$$

Factor

$$-\frac{1}{2} = -0.5$$