Solve (1/2)^2=2^3*0,125+2004^0+|-1|

$$( \frac { 1 } { 2 } ) ^ { 2 } = 2 ^ { 3 } \times 0,125 + 2004 ^ { 0 } + | - 1 |$$

Verify

Solution Steps

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{4}=2^{3}\times 0,125+2004^{0}+|-1|$$

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{4}=8\times 0,125+2004^{0}+|-1|$$

Multiply 8 and 0,125 to get 1.

$$\frac{1}{4}=1+2004^{0}+|-1|$$

Calculate 2004 to the power of 0 and get 1.

$$\frac{1}{4}=1+1+|-1|$$

Add 1 and 1 to get 2.

$$\frac{1}{4}=2+|-1|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -1 is 1.

$$\frac{1}{4}=2+1$$

Add 2 and 1 to get 3.

$$\frac{1}{4}=3$$

Convert 3 to fraction \frac{12}{4}.

$$\frac{1}{4}=\frac{12}{4}$$

Compare \frac{1}{4} and \frac{12}{4}.

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