Solve (1/2)^2+1/2+6

$$( \frac { 1 } { 2 } ) ^ { 2 } + \frac { 1 } { 2 } + 6$$

Evaluate

$$\frac{27}{4}=6.75$$

Solution Steps

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{4}+\frac{1}{2}+6$$

Least common multiple of 4 and 2 is 4. Convert \frac{1}{4} and \frac{1}{2} to fractions with denominator 4.

$$\frac{1}{4}+\frac{2}{4}+6$$

Since \frac{1}{4} and \frac{2}{4} have the same denominator, add them by adding their numerators.

$$\frac{1+2}{4}+6$$

Add 1 and 2 to get 3.

$$\frac{3}{4}+6$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{3}{4}+\frac{24}{4}$$

Since \frac{3}{4} and \frac{24}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+24}{4}$$

Add 3 and 24 to get 27.

$$\frac{27}{4}$$

Factor

$$\frac{3 ^ {3}}{2 ^ {2}} = 6\frac{3}{4} = 6.75$$