Solve (1/2+1/6)1/3

$$( \frac { 1 } { 2 } + \frac { 1 } { 6 } ) \frac { 1 } { 3 }$$

Evaluate

$$\frac{2}{9}\approx 0.222222222$$

Solution Steps

Least common multiple of 2 and 6 is 6. Convert \frac{1}{2} and \frac{1}{6} to fractions with denominator 6.

$$\left(\frac{3}{6}+\frac{1}{6}\right)\times \frac{1}{3}$$

Since \frac{3}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{3+1}{6}\times \frac{1}{3}$$

Add 3 and 1 to get 4.

$$\frac{4}{6}\times \frac{1}{3}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\frac{2}{3}\times \frac{1}{3}$$

Multiply \frac{2}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 1}{3\times 3}$$

Do the multiplications in the fraction \frac{2\times 1}{3\times 3}.

$$\frac{2}{9}$$

Factor

$$\frac{2}{3 ^ {2}} = 0.2222222222222222$$