Solve (1/2+1/6)^2:(1/4-1/36)=

$$( \frac { 1 } { 2 } + \frac { 1 } { 6 } ) ^ { 2 } : ( \frac { 1 } { 4 } - \frac { 1 } { 36 } ) =$$

Evaluate

$$2$$

Solution Steps

Add \frac{1}{2} and \frac{1}{6} to get \frac{2}{3}.

$$\frac{\left(\frac{2}{3}\right)^{2}}{\frac{1}{4}-\frac{1}{36}}$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{\frac{4}{9}}{\frac{1}{4}-\frac{1}{36}}$$

Subtract \frac{1}{36} from \frac{1}{4} to get \frac{2}{9}.

$$\frac{\frac{4}{9}}{\frac{2}{9}}$$

Divide \frac{4}{9} by \frac{2}{9} by multiplying \frac{4}{9} by the reciprocal of \frac{2}{9}.

$$\frac{4}{9}\times \frac{9}{2}$$

Multiply \frac{4}{9} and \frac{9}{2} to get 2.

$$2$$

Factor

$$2$$