Solve (1/18(3*3*3*3*3*3*3))-3

$$( \frac { 1 } { 18 } ( 3 * 3 * 3 * 3 * 3 * 3 * 3 ) ) - 3$$

Evaluate

$$\frac{237}{2}=118.5$$

Solution Steps

Multiply \frac{1}{18} and 3 to get \frac{3}{18}.

$$\frac{3}{18}\times 3\times 3\times 3\times 3\times 3\times 3-3$$

Reduce the fraction \frac{3}{18} to lowest terms by extracting and canceling out 3.

$$\frac{1}{6}\times 3\times 3\times 3\times 3\times 3\times 3-3$$

Multiply \frac{1}{6} and 3 to get \frac{3}{6}.

$$\frac{3}{6}\times 3\times 3\times 3\times 3\times 3-3$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}\times 3\times 3\times 3\times 3\times 3-3$$

Multiply \frac{1}{2} and 3 to get \frac{3}{2}.

$$\frac{3}{2}\times 3\times 3\times 3\times 3-3$$

Express \frac{3}{2}\times 3 as a single fraction.

$$\frac{3\times 3}{2}\times 3\times 3\times 3-3$$

Multiply 3 and 3 to get 9.

$$\frac{9}{2}\times 3\times 3\times 3-3$$

Express \frac{9}{2}\times 3 as a single fraction.

$$\frac{9\times 3}{2}\times 3\times 3-3$$

Multiply 9 and 3 to get 27.

$$\frac{27}{2}\times 3\times 3-3$$

Express \frac{27}{2}\times 3 as a single fraction.

$$\frac{27\times 3}{2}\times 3-3$$

Multiply 27 and 3 to get 81.

$$\frac{81}{2}\times 3-3$$

Express \frac{81}{2}\times 3 as a single fraction.

$$\frac{81\times 3}{2}-3$$

Multiply 81 and 3 to get 243.

$$\frac{243}{2}-3$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{243}{2}-\frac{6}{2}$$

Since \frac{243}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{243-6}{2}$$

Subtract 6 from 243 to get 237.

$$\frac{237}{2}$$

Factor

$$\frac{3 \cdot 79}{2} = 118\frac{1}{2} = 118.5$$