Solve (1/10-1/12)*(51/4+075)

$$( \frac { 1 } { 10 } - \frac { 1 } { 12 } ) \times ( 5 \frac { 1 } { 4 } + 075 )$$

Evaluate

$$\frac{7}{80}=0.0875$$

Solution Steps

Least common multiple of 10 and 12 is 60. Convert \frac{1}{10} and \frac{1}{12} to fractions with denominator 60.

$$\left(\frac{6}{60}-\frac{5}{60}\right)\left(\frac{5\times 4+1}{4}+0\times 75\right)$$

Since \frac{6}{60} and \frac{5}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-5}{60}\left(\frac{5\times 4+1}{4}+0\times 75\right)$$

Subtract 5 from 6 to get 1.

$$\frac{1}{60}\left(\frac{5\times 4+1}{4}+0\times 75\right)$$

Multiply 5 and 4 to get 20.

$$\frac{1}{60}\left(\frac{20+1}{4}+0\times 75\right)$$

Add 20 and 1 to get 21.

$$\frac{1}{60}\left(\frac{21}{4}+0\times 75\right)$$

Multiply 0 and 75 to get 0.

$$\frac{1}{60}\left(\frac{21}{4}+0\right)$$

Add \frac{21}{4} and 0 to get \frac{21}{4}.

$$\frac{1}{60}\times \frac{21}{4}$$

Multiply \frac{1}{60} times \frac{21}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 21}{60\times 4}$$

Do the multiplications in the fraction \frac{1\times 21}{60\times 4}.

$$\frac{21}{240}$$

Reduce the fraction \frac{21}{240} to lowest terms by extracting and canceling out 3.

$$\frac{7}{80}$$

Factor

$$\frac{7}{2 ^ {4} \cdot 5} = 0.0875$$