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\left(\frac{1+3}{2}\right)^{-1}+\left(\frac{1-\sqrt[3]{-9+1}}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Calculate the square root of 9 and get 3.
\left(\frac{4}{2}\right)^{-1}+\left(\frac{1-\sqrt[3]{-9+1}}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Add 1 and 3 to get 4.
2^{-1}+\left(\frac{1-\sqrt[3]{-9+1}}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Divide 4 by 2 to get 2.
\frac{1}{2}+\left(\frac{1-\sqrt[3]{-9+1}}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Calculate 2 to the power of -1 and get \frac{1}{2}.
\frac{1}{2}+\left(\frac{1-\sqrt[3]{-8}}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Add -9 and 1 to get -8.
\frac{1}{2}+\left(\frac{1-\left(-2\right)}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Calculate \sqrt[3]{-8} and get -2.
\frac{1}{2}+\left(\frac{1+2}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
The opposite of -2 is 2.
\frac{1}{2}+\left(\frac{3}{6}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Add 1 and 2 to get 3.
\frac{1}{2}+\left(\frac{1}{2}\right)^{2}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
\frac{1}{2}+\frac{1}{4}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{3}{4}+\left(\frac{8-\sqrt[5]{32}}{3}\right)^{-3}
Add \frac{1}{2} and \frac{1}{4} to get \frac{3}{4}.
\frac{3}{4}+\left(\frac{8-2}{3}\right)^{-3}
Calculate \sqrt[5]{32} and get 2.
\frac{3}{4}+\left(\frac{6}{3}\right)^{-3}
Subtract 2 from 8 to get 6.
\frac{3}{4}+2^{-3}
Divide 6 by 3 to get 2.
\frac{3}{4}+\frac{1}{8}
Calculate 2 to the power of -3 and get \frac{1}{8}.
\frac{7}{8}
Add \frac{3}{4} and \frac{1}{8} to get \frac{7}{8}.