Solve (-7/13+4/2)div5/3

$$( \frac { - 7 } { 13 } + \frac { 4 } { 2 } ) \div \frac { 5 } { 3 }$$

Evaluate

$$\frac{57}{65}\approx 0.876923077$$

Solution Steps

Fraction \frac{-7}{13} can be rewritten as -\frac{7}{13} by extracting the negative sign.

$$\frac{-\frac{7}{13}+\frac{4}{2}}{\frac{5}{3}}$$

Divide 4 by 2 to get 2.

$$\frac{-\frac{7}{13}+2}{\frac{5}{3}}$$

Convert 2 to fraction \frac{26}{13}.

$$\frac{-\frac{7}{13}+\frac{26}{13}}{\frac{5}{3}}$$

Since -\frac{7}{13} and \frac{26}{13} have the same denominator, add them by adding their numerators.

$$\frac{\frac{-7+26}{13}}{\frac{5}{3}}$$

Add -7 and 26 to get 19.

$$\frac{\frac{19}{13}}{\frac{5}{3}}$$

Divide \frac{19}{13} by \frac{5}{3} by multiplying \frac{19}{13} by the reciprocal of \frac{5}{3}.

$$\frac{19}{13}\times \frac{3}{5}$$

Multiply \frac{19}{13} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19\times 3}{13\times 5}$$

Do the multiplications in the fraction \frac{19\times 3}{13\times 5}.

$$\frac{57}{65}$$

Factor

$$\frac{3 \cdot 19}{5 \cdot 13} = 0.8769230769230769$$