Solve (-3/5*(1/2)^2)div(-1/8+3/5)

$$( \frac { - 3 } { 5 } \cdot ( \frac { 1 } { 2 } ) ^ { 2 } ) \div ( \frac { - 1 } { 8 } + \frac { 3 } { 5 } )$$

Evaluate

$$-\frac{6}{19}\approx -0.315789474$$

Solution Steps

Fraction \frac{-3}{5} can be rewritten as -\frac{3}{5} by extracting the negative sign.

$$\frac{-\frac{3}{5}\times \left(\frac{1}{2}\right)^{2}}{\frac{-1}{8}+\frac{3}{5}}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-\frac{3}{5}\times \frac{1}{4}}{\frac{-1}{8}+\frac{3}{5}}$$

Multiply -\frac{3}{5} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{-3}{5\times 4}}{\frac{-1}{8}+\frac{3}{5}}$$

Do the multiplications in the fraction \frac{-3}{5\times 4}.

$$\frac{\frac{-3}{20}}{\frac{-1}{8}+\frac{3}{5}}$$

Fraction \frac{-3}{20} can be rewritten as -\frac{3}{20} by extracting the negative sign.

$$\frac{-\frac{3}{20}}{\frac{-1}{8}+\frac{3}{5}}$$

Fraction \frac{-1}{8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$\frac{-\frac{3}{20}}{-\frac{1}{8}+\frac{3}{5}}$$

Least common multiple of 8 and 5 is 40. Convert -\frac{1}{8} and \frac{3}{5} to fractions with denominator 40.

$$\frac{-\frac{3}{20}}{-\frac{5}{40}+\frac{24}{40}}$$

Since -\frac{5}{40} and \frac{24}{40} have the same denominator, add them by adding their numerators.

$$\frac{-\frac{3}{20}}{\frac{-5+24}{40}}$$

Add -5 and 24 to get 19.

$$\frac{-\frac{3}{20}}{\frac{19}{40}}$$

Divide -\frac{3}{20} by \frac{19}{40} by multiplying -\frac{3}{20} by the reciprocal of \frac{19}{40}.

$$-\frac{3}{20}\times \frac{40}{19}$$

Multiply -\frac{3}{20} times \frac{40}{19} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\times 40}{20\times 19}$$

Do the multiplications in the fraction \frac{-3\times 40}{20\times 19}.

$$\frac{-120}{380}$$

Reduce the fraction \frac{-120}{380} to lowest terms by extracting and canceling out 20.

$$-\frac{6}{19}$$

Factor

$$-\frac{6}{19} = -0.3157894736842105$$