Solve (-2/3)^2+8/3:4/2

$$( \frac { - 2 } { 3 } ) ^ { 2 } + \frac { 8 } { 3 } : \frac { 4 } { 2 }$$

Evaluate

$$\frac{16}{9}\approx 1.777777778$$

Solution Steps

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$\left(-\frac{2}{3}\right)^{2}+\frac{\frac{8}{3}}{\frac{4}{2}}$$

Calculate -\frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{4}{9}+\frac{\frac{8}{3}}{\frac{4}{2}}$$

Divide \frac{8}{3} by \frac{4}{2} by multiplying \frac{8}{3} by the reciprocal of \frac{4}{2}.

$$\frac{4}{9}+\frac{8\times 2}{3\times 4}$$

Cancel out 4 in both numerator and denominator.

$$\frac{4}{9}+\frac{2\times 2}{3}$$

Multiply 2 and 2 to get 4.

$$\frac{4}{9}+\frac{4}{3}$$

Add \frac{4}{9} and \frac{4}{3} to get \frac{16}{9}.

$$\frac{16}{9}$$

Factor

$$\frac{2 ^ {4}}{3 ^ {2}} = 1\frac{7}{9} = 1.7777777777777777$$