Solve (-2/3+sqrt[4]{1/16})^149

$$( \frac { - 2 } { 3 } + \sqrt[ 4 ] { \frac { 1 } { 16 } } ) ^ { 149 }$$

Evaluate

$$-\frac{1}{88010868599026422987009889617668753739226459584613284587347581631730566855845151281843301456034827048118117933776896}\approx -1.136223305 \cdot 10^{-116}$$

Solution Steps

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$\left(-\frac{2}{3}+\sqrt[4]{\frac{1}{16}}\right)^{149}$$

Calculate \sqrt[4]{\frac{1}{16}} and get \frac{1}{2}.

$$\left(-\frac{2}{3}+\frac{1}{2}\right)^{149}$$

Add -\frac{2}{3} and \frac{1}{2} to get -\frac{1}{6}.

$$\left(-\frac{1}{6}\right)^{149}$$

Calculate -\frac{1}{6} to the power of 149 and get -\frac{1}{88010868599026422987009889617668753739226459584613284587347581631730566855845151281843301456034827048118117933776896}.

$$-\frac{1}{88010868599026422987009889617668753739226459584613284587347581631730566855845151281843301456034827048118117933776896}$$

Factor

$$-\frac{1}{88010868599026422987009889617668753739226459584613284587347581631730566855845151281843301456034827048118117933776896} = -1.136223305051056 \times 10^{-116}$$