Solve (-1/25)^2+2^-3-(1/8)

$$( \frac { - 1 } { 25 } ) ^ { 2 } + 2 ^ { - 3 } - ( \frac { 1 } { 8 } )$$

Evaluate

$$\frac{1}{625}=0.0016$$

Solution Steps

Fraction \frac{-1}{25} can be rewritten as -\frac{1}{25} by extracting the negative sign.

$$\left(-\frac{1}{25}\right)^{2}+2^{-3}-\frac{1}{8}$$

Calculate -\frac{1}{25} to the power of 2 and get \frac{1}{625}.

$$\frac{1}{625}+2^{-3}-\frac{1}{8}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{1}{625}+\frac{1}{8}-\frac{1}{8}$$

Add \frac{1}{625} and \frac{1}{8} to get \frac{633}{5000}.

$$\frac{633}{5000}-\frac{1}{8}$$

Subtract \frac{1}{8} from \frac{633}{5000} to get \frac{1}{625}.

$$\frac{1}{625}$$

Factor

$$\frac{1}{5 ^ {4}} = 0.0016$$