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\left(\frac{\sqrt{7}+\sqrt{3}+\sqrt{7}-\sqrt{3}}{2}\right)^{2}
Since \frac{\sqrt{7}+\sqrt{3}}{2} and \frac{\sqrt{7}-\sqrt{3}}{2} have the same denominator, add them by adding their numerators.
\left(\frac{2\sqrt{7}}{2}\right)^{2}
Do the calculations in \sqrt{7}+\sqrt{3}+\sqrt{7}-\sqrt{3}.
\left(\sqrt{7}\right)^{2}
Cancel out 2 and 2.
7
The square of \sqrt{7} is 7.