Solve (frac{sqrt{2x-9}-1}{1+sqrt[3]{9-2x}})=

$$( \frac { \sqrt { 2 x - 9 } - 1 } { 1 + \sqrt[ 3 ] { 9 - 2 x } } ) =$$

Evaluate

$$\frac{\left(\sqrt{-\left(9-2x\right)}-1\right)\left(\left(9-2x\right)^{\frac{2}{3}}-\sqrt[3]{9-2x}+1\right)}{2\left(5-x\right)}$$

Differentiate w.r.t. x

$$\frac{8\sqrt[3]{9-2x}x^{2}-3\left(9-2x\right)^{\frac{7}{3}}-3x\left(9-2x\right)^{\frac{4}{3}}+2x^{2}-4\sqrt[3]{9-2x}\sqrt{-\left(9-2x\right)}x-3\sqrt{-\left(9-2x\right)}\left(9-2x\right)^{\frac{4}{3}}+3\left(9-2x\right)^{\frac{2}{3}}x-4\sqrt{-\left(9-2x\right)}x-76\sqrt[3]{9-2x}x+15\left(9-2x\right)^{\frac{4}{3}}-3\sqrt{-\left(9-2x\right)}\left(9-2x\right)^{\frac{2}{3}}-13x+20\sqrt[3]{9-2x}\sqrt{-\left(9-2x\right)}-12\left(9-2x\right)^{\frac{2}{3}}+17\sqrt{-\left(9-2x\right)}+180\sqrt[3]{9-2x}+18}{6\sqrt{-\left(9-2x\right)}\left(9-2x\right)^{\frac{2}{3}}\left(5-x\right)^{2}}$$