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\frac{\left(\sqrt{17}+1\right)^{2}}{4^{2}}+\left(\frac{1-\sqrt{17}}{4}\right)^{2}
To raise \frac{\sqrt{17}+1}{4} to a power, raise both numerator and denominator to the power and then divide.
\frac{\left(\sqrt{17}+1\right)^{2}}{4^{2}}+\frac{\left(1-\sqrt{17}\right)^{2}}{4^{2}}
To raise \frac{1-\sqrt{17}}{4} to a power, raise both numerator and denominator to the power and then divide.
\frac{\left(\sqrt{17}+1\right)^{2}+\left(1-\sqrt{17}\right)^{2}}{4^{2}}
Since \frac{\left(\sqrt{17}+1\right)^{2}}{4^{2}} and \frac{\left(1-\sqrt{17}\right)^{2}}{4^{2}} have the same denominator, add them by adding their numerators.
\frac{\left(\sqrt{17}\right)^{2}+2\sqrt{17}+1}{4^{2}}+\frac{\left(1-\sqrt{17}\right)^{2}}{4^{2}}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{17}+1\right)^{2}.
\frac{17+2\sqrt{17}+1}{4^{2}}+\frac{\left(1-\sqrt{17}\right)^{2}}{4^{2}}
The square of \sqrt{17} is 17.
\frac{18+2\sqrt{17}}{4^{2}}+\frac{\left(1-\sqrt{17}\right)^{2}}{4^{2}}
Add 17 and 1 to get 18.
\frac{18+2\sqrt{17}}{16}+\frac{\left(1-\sqrt{17}\right)^{2}}{4^{2}}
Calculate 4 to the power of 2 and get 16.
\frac{18+2\sqrt{17}}{16}+\frac{1-2\sqrt{17}+\left(\sqrt{17}\right)^{2}}{4^{2}}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(1-\sqrt{17}\right)^{2}.
\frac{18+2\sqrt{17}}{16}+\frac{1-2\sqrt{17}+17}{4^{2}}
The square of \sqrt{17} is 17.
\frac{18+2\sqrt{17}}{16}+\frac{18-2\sqrt{17}}{4^{2}}
Add 1 and 17 to get 18.
\frac{18+2\sqrt{17}}{16}+\frac{18-2\sqrt{17}}{16}
Calculate 4 to the power of 2 and get 16.
\frac{18+2\sqrt{17}+18-2\sqrt{17}}{16}
Since \frac{18+2\sqrt{17}}{16} and \frac{18-2\sqrt{17}}{16} have the same denominator, add them by adding their numerators.
\frac{36}{16}
Do the calculations in 18+2\sqrt{17}+18-2\sqrt{17}.