Solve (3/2/-frac{9{8}}+1/3)

$$( \frac { \frac { 3 } { 2 } } { - \frac { 9 } { 8 } } + \frac { 1 } { 3 } )$$

Evaluate

$$-1$$

Solution Steps

Divide \frac{3}{2} by -\frac{9}{8} by multiplying \frac{3}{2} by the reciprocal of -\frac{9}{8}.

$$\frac{3}{2}\left(-\frac{8}{9}\right)+\frac{1}{3}$$

Multiply \frac{3}{2} times -\frac{8}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(-8\right)}{2\times 9}+\frac{1}{3}$$

Do the multiplications in the fraction \frac{3\left(-8\right)}{2\times 9}.

$$\frac{-24}{18}+\frac{1}{3}$$

Reduce the fraction \frac{-24}{18} to lowest terms by extracting and canceling out 6.

$$-\frac{4}{3}+\frac{1}{3}$$

Since -\frac{4}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{-4+1}{3}$$

Add -4 and 1 to get -3.

$$\frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$-1$$

Factor

$$-1$$