Solve (+5+7-4)=+8ab^4

$$( + 5 + 7 - 4 ) = + 8 a b ^ { 4 }$$

Solve for a

$$a=\frac{1}{b^{4}}$$

$$b\neq 0$$

Steps for Solving Linear Equation

Add 5 and 7 to get 12.

$$12-4=8ab^{4}$$

Subtract 4 from 12 to get 8.

$$8=8ab^{4}$$

Swap sides so that all variable terms are on the left hand side.

$$8ab^{4}=8$$

The equation is in standard form.

$$8b^{4}a=8$$

Divide both sides by 8b^{4}.

$$\frac{8b^{4}a}{8b^{4}}=\frac{8}{8b^{4}}$$

Dividing by 8b^{4} undoes the multiplication by 8b^{4}.

$$a=\frac{8}{8b^{4}}$$

Divide 8 by 8b^{4}.

$$a=\frac{1}{b^{4}}$$

Solve for b (complex solution)

$$b=ia^{-\frac{1}{4}}$$

$$b=a^{-\frac{1}{4}}$$

$$b=-a^{-\frac{1}{4}}$$

$$b=-ia^{-\frac{1}{4}}\text{, }a\neq 0$$

Solve for b

$$b=\frac{1}{\sqrt[4]{a}}$$

$$b=-\frac{1}{\sqrt[4]{a}}\text{, }a>0$$