Solve (+1/2)-(+2/3)+(-11/6)=

$$( + \frac { 1 } { 2 } ) - ( + \frac { 2 } { 3 } ) + ( - 1 \frac { 1 } { 6 } ) =$$

Evaluate

$$-\frac{4}{3}\approx -1.333333333$$

Solution Steps

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{2}{3} to fractions with denominator 6.

$$\frac{3}{6}-\frac{4}{6}-\frac{1\times 6+1}{6}$$

Since \frac{3}{6} and \frac{4}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-4}{6}-\frac{1\times 6+1}{6}$$

Subtract 4 from 3 to get -1.

$$-\frac{1}{6}-\frac{1\times 6+1}{6}$$

Multiply 1 and 6 to get 6.

$$-\frac{1}{6}-\frac{6+1}{6}$$

Add 6 and 1 to get 7.

$$-\frac{1}{6}-\frac{7}{6}$$

Since -\frac{1}{6} and \frac{7}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-7}{6}$$

Subtract 7 from -1 to get -8.

$$\frac{-8}{6}$$

Reduce the fraction \frac{-8}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{4}{3}$$

Factor

$$-\frac{4}{3} = -1\frac{1}{3} = -1.3333333333333333$$