Solve (+1/2)+(+2/3)-(-11/6)

$$( + \frac { 1 } { 2 } ) + ( + \frac { 2 } { 3 } ) - ( - 1 \frac { 1 } { 6 } )$$

Evaluate

$$\frac{7}{3}\approx 2.333333333$$

Solution Steps

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{2}{3} to fractions with denominator 6.

$$\frac{3}{6}+\frac{4}{6}-\left(-\frac{1\times 6+1}{6}\right)$$

Since \frac{3}{6} and \frac{4}{6} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{6}-\left(-\frac{1\times 6+1}{6}\right)$$

Add 3 and 4 to get 7.

$$\frac{7}{6}-\left(-\frac{1\times 6+1}{6}\right)$$

Multiply 1 and 6 to get 6.

$$\frac{7}{6}-\left(-\frac{6+1}{6}\right)$$

Add 6 and 1 to get 7.

$$\frac{7}{6}-\left(-\frac{7}{6}\right)$$

The opposite of -\frac{7}{6} is \frac{7}{6}.

$$\frac{7}{6}+\frac{7}{6}$$

Since \frac{7}{6} and \frac{7}{6} have the same denominator, add them by adding their numerators.

$$\frac{7+7}{6}$$

Add 7 and 7 to get 14.

$$\frac{14}{6}$$

Reduce the fraction \frac{14}{6} to lowest terms by extracting and canceling out 2.

$$\frac{7}{3}$$

Factor

$$\frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335$$