Solve (+1/2)+(+2/3)+(-11/6)=

$$( + \frac { 1 } { 2 } ) + ( + \frac { 2 } { 3 } ) + ( - 1 \frac { 1 } { 6 } ) =$$

Evaluate

$$0$$

Solution Steps

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{2}{3} to fractions with denominator 6.

$$\frac{3}{6}+\frac{4}{6}-\frac{1\times 6+1}{6}$$

Since \frac{3}{6} and \frac{4}{6} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{6}-\frac{1\times 6+1}{6}$$

Add 3 and 4 to get 7.

$$\frac{7}{6}-\frac{1\times 6+1}{6}$$

Multiply 1 and 6 to get 6.

$$\frac{7}{6}-\frac{6+1}{6}$$

Add 6 and 1 to get 7.

$$\frac{7}{6}-\frac{7}{6}$$

Subtract \frac{7}{6} from \frac{7}{6} to get 0.

$$0$$

Factor

$$0$$