Solve |3-5|-(pi-3.14)^0+(-2)^-1+sin30^circ

$$| 3 - 5 | - ( \pi - 3.14 ) ^ { 0 } + ( - 2 ) ^ { - 1 } + \sin 30 ^ { \circ }$$

Evaluate

$$1$$

Solution Steps

Subtract 5 from 3 to get -2.

$$|-2|-\left(\pi -3.14\right)^{0}+\left(-2\right)^{-1}+\sin(30)$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.

$$2-\left(\pi -3.14\right)^{0}+\left(-2\right)^{-1}+\sin(30)$$

Calculate \pi -3.14 to the power of 0 and get 1.

$$2-1+\left(-2\right)^{-1}+\sin(30)$$

Subtract 1 from 2 to get 1.

$$1+\left(-2\right)^{-1}+\sin(30)$$

Calculate -2 to the power of -1 and get -\frac{1}{2}.

$$1-\frac{1}{2}+\sin(30)$$

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\frac{1}{2}+\sin(30)$$

Get the value of \sin(30) from trigonometric values table.

$$\frac{1}{2}+\frac{1}{2}$$

Add \frac{1}{2} and \frac{1}{2} to get 1.

$$1$$